— ## What are Force Components? Force components are the perpendicular parts of a single force vector that, when added together, produce the original vector. Imagine a force pushing a lawnmower: part of the force pushes it forward (horizontal component), and part of it pushes it into the ground (vertical component). Breaking a vector into its components is also called resolving the vector. ### Why Resolve Forces? * Simplifying Problems: It allows you to analyze motion independently along perpendicular axes (e.g., horizontal motion and vertical motion). * Applying Newton’s Laws: Newton’s Second Law ($\Sigma F = ma$) is applied separately to the sum of forces in the x-direction and the sum of forces in the y-direction. * Adding Forces: When adding multiple forces that aren’t all along the same axis, resolving them into components is often the easiest way to find the resultant (net) force. — ## How to Resolve Forces (Using Trigonometry) To resolve a force vector $\vec{F}$ with magnitude $F$ and angle $\theta$ (measured counter-clockwise from the positive x-axis) into its x and y components ($F_x$ and $F_y$), we use basic trigonometry: * Horizontal (x) Component: $F_x = F \cos(\theta)$ * Vertical (y) Component: $F_y = F \sin(\theta)$ Remember: * $\theta$ is the angle between the vector and the positive x-axis. If the angle is given differently (e.g., from the y-axis, or in a different quadrant), you’ll need to adjust it to fit this standard definition. * The signs of $F_x$ and $F_y$ will automatically be correct if $\theta$ is measured from the positive x-axis (e.g., in Quadrant II, $\cos(\theta)$ will be negative, giving a negative $F_x$). — ## Interactive: Force Component Resolver Adjust the magnitude and angle of the force vector to see its horizontal and vertical components change dynamically. <div class="animator-container"> <div class="input-controls"> 50 N 30° </div> <div style="margin-bottom: 0.8rem;"> </div> Force Vector Component Resolver An interactive visualization demonstrating how a force vector is resolved into its horizontal (x) and vertical (y) components. (0,0) +X +Y $F$ $F_x$ $F_y$ θ Magnitude: 0 N Angle: 0° Fx: 0.0 N Fy: 0.0 N <div id="animationExplanation" class="animation-explanation" aria-live="polite"> <p>Adjust the force’s magnitude and angle to see its components dynamically change.

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When Components are Negative

The signs of your components ($F_x$ and $F_y$) indicate their direction. If $F_x$ is negative, the component points in the negative x-direction (left). If $F_y$ is negative, it points in the negative y-direction (down).

This is automatically handled if you consistently measure your angle $\theta$ counter-clockwise from the positive x-axis.

Example Quadrants:

  • Quadrant I (0° to 90°): Both $F_x$ and $F_y$ are positive.
  • Quadrant II (90° to 180°): $F_x$ is negative, $F_y$ is positive.
  • Quadrant III (180° to 270°): Both $F_x$ and $F_y$ are negative.
  • Quadrant IV (270° to 360°): $F_x$ is positive, $F_y$ is negative.

Audio Explanation

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💡 Quick Concept Check:

A force of 100 N acts at an angle of 150° from the positive x-axis. What are its horizontal (x) and vertical (y) components?

Click to Reveal Answer
* $F_x = F \cos(\theta) = 100 \text{ N} \cdot \cos(150^\circ) = 100 \text{ N} \cdot (-0.866) = -86.6 \text{ N}$ * $F_y = F \sin(\theta) = 100 \text{ N} \cdot \sin(150^\circ) = 100 \text{ N} \cdot (0.5) = 50.0 \text{ N}$ The force has a horizontal component of 86.6 N to the left, and a vertical component of 50.0 N upwards.

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Practice Problems

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